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\(x^2-3x+5=0\) সমীকরণকে \(ax^2+bx+c=0\) সমীকরনের সঙ্গে তুলনা করে পাই, \(a=1, b=-3, c=5\)
\(\alpha +\beta=-\cfrac{-3}{1}=3\)
\(\alpha\beta=\cfrac{5}{1}=5\)
\(\therefore (\alpha+\beta)\left(\cfrac{1}{\alpha^2}+\cfrac{1}{\beta^2}\right)\)
\(= (\alpha+\beta)\left(\cfrac{\alpha^2+\beta^2}{\alpha^2 \beta^2}\right)\)
\(= (\alpha+\beta)\left(\cfrac{\alpha^2+\beta^2}{\alpha^2 \beta^2}\right)\)