\(\angle P+\angle Q=90°\) হলে দেখাও যে, \(\sqrt{\cfrac{sin P}{cos Q}-sin P cos Q}=cos P\)
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\(\sqrt{\cfrac{\sin P}{\cos Q}-\sin P \cos Q}\)
\(=\sqrt{\cfrac{\sin P}{\cos (90°-P)}-\sin P \cos (90°-P)}\)
\(=\sqrt{\cfrac{\sin P}{\sin P}-\sin P \sin P}\)
\(=\sqrt{\cfrac{\sin P}{\sin P}-\sin^2 P }\)
\(=\sqrt{1-\sin^2 P }\)
\(=\sqrt{\cos^2 P }\)
\(=cosP\) (প্রমানিত)
