বৃত্তীয় মান নির্ণয় করি : 40°16'24"
\(40°16'24''=40°+16'+24''\)
\(=40°+16'+{\cfrac{24}{60}}^{'}\)
\(= 40°+\left(16+\cfrac{2}{5}\right)^{'}\)
\(=40°+\left(\cfrac{80+2}{5}\right)^{'}\)
\(= 40°+{\cfrac{82}{5×60}}^o\)
\(=40°+{\cfrac{41}{150}}^o\)
\(={\cfrac{6000+41}{150}}^o\)
\(= {\cfrac{6041}{150}}^o\)
\(∵180°=π^c\)
\(∴{\cfrac{6041}{150}}^o=\cfrac{π^c}{180}×\cfrac{6041}{150}={\cfrac{6041π}{27000}}^c\)
\(∴ 40°16'24''={\cfrac{6041π}{27000}}^c\) (Answer)