দেখাই যে, \(3\sqrt{48}-4\sqrt{75}+\sqrt{192}=0\)
\(3\sqrt{48}-4\sqrt{75}+\sqrt{192}\)
\(=3\sqrt{(2×2×2×2×3}-4\sqrt{3×5×5} \) \(+\sqrt{2×2×2×2×2×2×3}\)
\(=3×4\sqrt{3}-4×5\sqrt{3}+8\sqrt{3}\)
\(=12\sqrt{3}-20\sqrt{3}+8\sqrt{3}\)
\(=20\sqrt{3}-20\sqrt{3}=0\) [প্রমাণিত]