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বিবৃতিটি সত্য ।

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\(sin\cfrac{\pi}{6}+sin\cfrac{\pi}{3}\)
\(=\cfrac{1}{2}+\cfrac{\sqrt{3}}{2}\)
\(=\cfrac{1+\sqrt3}{2}\)

\(sin\cfrac{\pi}{2}\)
\(=1\)

\(\because \cfrac{1+\sqrt3}{2} >1\)
\(\therefore sin\cfrac{\pi}{6}+sin\cfrac{\pi}{3}\)