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\(\cfrac{2 sin^2⁡ 63° +1+2 sin^2⁡ 27°}{3 cos^2⁡ 17° -2+3 cos^2⁡ 73°}\)
\(=\cfrac{2 sin^2⁡ 63° +1+2 sin^2⁡(90°-63°)}{3 cos^2⁡(90°-73°)-2+3 cos^2⁡ 73°}\)
\(=\cfrac{2 sin^2⁡ 63° +1+2 cos^2⁡ 63° }{3 sin^2⁡ 73° -2+3 cos^2⁡ 73° }\)
\(= \cfrac{2 (sin^2 ⁡ 63° +cos^2⁡ 63° )+1}{3 (sin^2 ⁡ 73°+ cos^2⁡ 73°) -2}\)
\(=\cfrac{2+1}{3-2}\)
\(=\cfrac{3}{1}\)
\(=3\) (Answer)