1. দেখাও যে, \(\cfrac{tan \theta+ sec \theta -1}{tan \theta - sec\theta +1}=\cfrac{1+sin \theta}{cos\theta}\)

2. \(\cfrac{tan\theta+sec\theta-1}{tan\theta-sec\theta+1}\) এর মান হল -

(a) \(\cfrac{1+cos\theta}{sin\theta}\) (b) \(\cfrac{1+sin\theta}{cos\theta}\) (c) \(\cfrac{1+tan\theta}{sec\theta}\) (d) \(\cfrac{1+sec\theta}{sin\theta}\)

3. \(\cfrac{sec\theta+1}{tan\theta}=x\) হলে \(\cfrac{sec\theta-1}{tan\theta}\)-এর মান হল :

(a) \(\frac{1}{x}\) (b) \(x\) (c) \(2x\) (d) \(3x\)