সমাধান করো :
\(\cfrac{x+3}{x-3}+\cfrac{x-3}{x+3}=2\cfrac{1}{2} [x≠3,-3]\) Madhyamik 2025
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\(\cfrac{x+3}{x-3}+\cfrac{x-3}{x+3}=2\cfrac{1}{2}\)
বা, \(\cfrac{(x+3)^2+(x-3)^2}{(x-3)(x+3)}=\cfrac{5}{2}\)
বা, \(\cfrac{2(x^2+3^2)}{x^2-9}=\cfrac{5}{2}\)
বা, \(\cfrac{2x^2+18)}{x^2-9}=\cfrac{5}{2}\)
বা, \(4x^2+36=5x^2-45\)
বা, \(-x^2=-45-36\)
বা, \(x^2=81\)
বা, \(x=\pm 9\)

\(\therefore\) নির্ণেয় সমাধান \(x=9, -9\)

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