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\(\because\) \( 60' =1°\)
$$ \require{enclose} \begin{array}{r} 13 \\[-3pt] 60 \enclose{longdiv}{832} \\[-3pt] \underline{60}\phantom{2} \\[-3pt] 232 \\[-3pt] \underline{180} \\[-3pt] 52 \\[-3pt] \end{array} $$
\(\therefore\) 832'=13°52' (Answer)