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$$ \require{enclose} \begin{array}{rll} 105&& \\[-3pt] 60 \enclose{longdiv}{6312}\kern-.2ex \\[-3pt] \underline{60\phantom{00}} && \\[-3pt] \phantom{0}312 && \\[-3pt] \underline{\phantom{0}300} && \\[-3pt] \phantom{0}12 && \\[-3pt] \end{array} $$ \(\therefore 6312''=105' 12''\)
$$ \require{enclose} \begin{array}{rll} 1\phantom{00}&& \\[-3pt] 60 \enclose{longdiv}{105}\kern-.2ex \\[-3pt] \underline{\phantom{00}60} && \\[-3pt] \phantom{0}45 && \\[-3pt] \end{array} $$ \(\therefore 6312''=1^o45'12''\) (Answer)