\( tan\theta=\cfrac{4}{3}\) হলে, \(sin\theta +cos\theta\) =কত?
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\( tan\theta=\cfrac{4}{3}\)
ধরি, লম্ব = 4 একক এবং ভূমি =3 একক ।
\(\therefore\) অতিভূজ \(=\sqrt{4^2+3^2}\)
\(=\sqrt{16+9}\)
\(=\sqrt{25}=5\) একক
\(sin\theta +cos\theta\)
=লম্ব/অতিভূজ +ভূমি /অতিভূজ
\(=\cfrac{4}{5}+\cfrac{3}{5}\)
\(=\cfrac{4+3}{5}\)
\(=\cfrac{7}{5}\) [Answer]