\(\cos (40°+θ)-\sin(50–θ)\)-এর মান (a) \(2\cosθ\) (b) \(7\sinθ\) (c) 0 (d) 1

Answer: C
\(cos⁡(40°+θ)-sin⁡ (50°-θ)\)
\(=cos⁡(40°+θ)-sin⁡[90°-(40°+θ)]\)
\(=cos⁡ (40°+θ)-cos⁡(40°+θ) \)
\(=0\)

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