\(x=3+2\sqrt2\) হলে, \(x+\cfrac{1}{x}\) এর মান লিখি ।


\(x=3+2√2\)
\(\therefore \cfrac{1}{x}=\cfrac{1}{3+2√2}\)
\(=\cfrac{(3-2√2)}{(3+2√2)(3-2√2)}\)
\(=\cfrac{(3-2√2)}{(3)^2-(2√2)^2}\)
\(=\cfrac{(3-2√2)}{9-8}\)
\(=\cfrac{(3-2√2)}{1}=3-2√2\)

\(\therefore x+\cfrac{1}{x}=3+2√2+3-2√2=6\)

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