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\(\cfrac{1}{x}=\cfrac{1}{(2+√3)} \)
\(=\cfrac{(2-√3)}{(2+√3)(2-√3)}\)
\(=\cfrac{(2-√3)}{(2)^2-(√3)^2} \)
\(=\cfrac{2-√3}{4-3} \)
\(=2-√3\)

\(∴ x-\cfrac{1}{x}=(2+√3)-(2-√3)\)
\(=2+√3-2+√3\)
\(=2√3\)

\(\therefore x^3-\cfrac{1}{x^3}=\left(x-\cfrac{1}{x}\right)^3+3\cdot x \cdot \cfrac {1}{x}\left(x-\cfrac{1}{x}\right)\)
\(=(2\sqrt3)^3+3\times 2\sqrt3\)
\(=24\sqrt3+6\sqrt3\)
\(=30\sqrt3\) [Answer]


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