যদি \(sin\theta+cosec\theta\)=2 হয়, তাহলে প্রমাণ করো \(sin^{99}\theta+cosec ^{99}\theta\)=2
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\(sin\theta+cosec\theta=2 \)
বা, \(sin\theta+\cfrac{1}{sin\theta}=2 \)
বা, \(\cfrac{sin^2\theta+1}{sin\theta}=2 \)
বা, \(sin^2\theta+1=2sin\theta \)
বা, \(sin^2\theta+1-2sin\theta =0\)
বা, \((sin\theta-1)^2=0\)
বা, \(sin\theta-1=0\)
বা, \(sin\theta=1\)
\(\therefore cosec \theta=\cfrac{1}{sin \theta}=1\)
\(\therefore sin^{99}\theta+cosec ^{99}\theta =(1)^{99}+(1)^{99}=1+1=2\) [প্রমানিত]