sin30° +sin60°>sin90°।
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বিবৃতিটি সত্য ।
\( sin30° +sin60° \)
\(=\cfrac{1}{2}+\cfrac{\sqrt3}{2}\)
\(=\cfrac{1+\sqrt3}{2}\)
\(\because \sqrt3\approx 1.732 \therefore 1+\sqrt3 \approx2.732\gt 2\)
\(\therefore \cfrac{1+\sqrt3}{2} \gt 1\)
\(sin 90^o=1\)
\(\therefore sin30° +sin60° \gt sin90°\)
