\( x=3+2√2\) এবং \(xy=1\) হলে \(\cfrac{x^2 + y^2}{xy}\) এর মান কত?
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\(xy=1\)
বা, \(y=\cfrac{1}{x}\)
\(=\cfrac{1}{3+2\sqrt2}\)
\(=\cfrac{(3-2\sqrt2)}{(3+2\sqrt2)(3-2\sqrt2)}\)
\(=\cfrac{3-2\sqrt2}{(3)^2-(2\sqrt2)^2}\)
\(=\cfrac{3-2\sqrt2}{9-8}\)
\(=3-2\sqrt2\)
\(\therefore x+y=3+2\sqrt2+3-2\sqrt2 =6\)
\( \cfrac{x^2+y^2}{xy}\)
\(=\cfrac{(x+y)^2-2xy}{xy}\)
\(=\cfrac{(6)^2-2\times 1}{1}\)
\(=36-2\)
\(=34\) [Answer]
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